Research for Bowling ball drop

The bowling ball has been dropped from an approximate height of 1 metre

Animate the bowling ball entering the shot from the top demonstrating its characteristics.

Fully rendered shot (looped 3 times)

QuickTime format – h.264 – 1920x1080 square pixel 25fps

Research - 

•  Falling bowling ball

Timecode on After effects allows you to put a composition of a live bowling ball dropping and see the frame rate so i can accuraetly recreate the sequence.

• Facts
• A bowling ball weights between 2,7 to 7,3 kilograms.
• Bowling balls were made out of wood until the early 1900s.
• Bowling is the number one participation sport in America.
• The origins of bowling can be traced about 4,000 years back to Rome and Greece.

If a bowling ball and a tennis ball were dropped at the same height, assuming they have they same aerodynamic values, that is they are they same shape and same size they will hit the ground at the same time. Weight has nothing to do with it, only wind resistance does. Gravity's force is constant. No matter the weight it is 9.8 meters per second. The pull of gravity is the same on the bowling ball as on the tennis ball. You can take a cannon ball and a bowling ball, of the same size and they will fall at the same speed and hit the ground at the same time even though the bowling ball only weighs 7 pounds and the cannonball weighs 50 pounds.

This leads me to look into Newtons law of Gravitation, according to the Newton gravitation (remember that it's just an approximation), the force acting on a body of mass m₂ in r₂ caused by a body of mass m₁ in r₁ (in this case, the Earth) is 

F (force) = - G (gravitation) m₁m₂ (r₂ - r₁)/|r₂ - r₁|³, 
with G constant. 

Using the Newton equation for the body 2 (F = m₂ d²r₂/dt²), we have 
- G m₁m₂ (r₂ - r₁)/|r₂ - r₁|³ = m₂ d²r₂/dt² → 

→ - G m₁ (r₂ - r₁)/|r₂ - r₁|³ = d²r₂/dt². 

Now, if you assume that r₁ = 0 and consider bodies that are not too distant from the ground, you may approximate r₂ = r_T + r (r_T is the Earth radius) with r_T, that is a constant. And so the acceleration of any body is

d²r/dt² = d²⁽r_T + r)/dt² ≈ - G m₁ r_T/|r_T|³,


and so you see this acceleration is constant (it's the famous "g"), independent from the mass m₂ of the falling body. (Note that, even without our assumptions, the acceleration does not depend on m₂: this is due to the form of Newton gravitation law and Newton equation, and it is the heart of the equivalence between gravitational and inertial mass).  

*** There is a difference between speed (or velocity) and acceleration. They are, of course, related, but acceleration is the rate of change of velocity. When you are sitting in your car at a red light and the light turns green and you step on the gas (or accelerator!), your car accelerates from zero to some final velocity (hopefully not much more than the posted speed limit). Your speedometer clearly shows the change in velocity as the needle moves clockwise. The faster that needle moves, the greater the acceleration. 
On Earth, objects do not fall at constant speed, as your question suggests. Gravity accelerates objects toward the center of the Earth at 32.2 ft per second per second (which can also be written as 32 ft/s²). In other words, an object's velocity will increase by 32.2 ft/s (or 9.8 m/s) for each second the object falls until it reaches its terminal velocity, which you can think of as a kind of speed limit. Terminal velocity is reached when air friction equally opposes the force of gravity. Different objects will have different terminal velocities, depending upon their shapes.  ***

Imagine you are on top of a tall building and holding a bowling ball over the side of the building. At time t = 0 seconds, you let go of the ball. At that exact moment, the ball is traveling at 0 ft/s, but as the ball experiences gravity without your holding it, it starts to fall. After one second, the ball will be traveling 32.2 ft/s. After two seconds, it is traveling 64.4 ft/s, and after three seconds, it is traveling at 96.6 ft/s. 
So you see that falling objects do not fall at the constant rate of 32.2 feet per second but actually accelerate -- that is, pick up speed -- at a rate of 32.2 feet per second per second. 

http://wiki.answers.com/Q/Does_gravity_pull_things_down_32.2_feet_per_second